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如何赢得虚空之眼与大发明家的对抗赛虚空之眼 is in the a tier of champions

虚空之眼 vs 大发明家

如何在LoL中以虚空之眼的身份击败大发明家虚空之眼 is in the b tier of champions
Mage
MageSupport

如何击败大发明家成为虚空之眼

based on 1,258 虚空之眼 vs 大发明家 matchups
胜率
49.2 %
kda
2.38
受欢迎度
1.6 %

How We Analyze LoL Champion Counters

We calculate our matchup statistics from the millions of rated League matches that we review every week. This guide on how to beat 大发明家 as 虚空之眼 came out of an analysis of 1258 ranked games where both champions battled one another. This pairing is fairly rare. 虚空之眼 is forced to battle against 大发明家 in only 1.6% of his rounds.

虚空之眼 vs 大发明家 Matchup Summary

Unfortunately, 虚空之眼 does a poor job of countering 大发明家. On average, he wins a acceptable 49.2% of the time the champs fight each other in. In 虚空之眼 against 大发明家 rounds, 虚空之眼’s team is 0.1% more expected to earn first blood. This implies that he most likely will get first blood versus 大发明家.

counterTitle

物品

第一项

期望时间
生命药水云游图鉴

下一个项目

5分钟
增幅典籍荧尘

Core 虚空之眼 Items

22分钟
残疫扎兹沙克的溃口卢登的伙伴

可选项目

炽天使之拥影焰视界专注兰德里的折磨

Summoner Spells

summonerflash summoner spell D
summonerdot summoner spell F

技能顺序

为虚空之眼提升等级的第一个技能q
>
为虚空之眼提供的第二种能力,以提高水平w
>
虚空之眼 最大化的最后一项技能e

符文

巫术奥术彗星法力流系带超然焦灼
启迪饼干配送星界洞悉
Adaptive ForceAdaptive ForceMagic Resist
虚空之眼's passive ability p
虚空之眼's q ability q
虚空之眼's w ability w
虚空之眼's e ability e
虚空之眼's ultimate ability r
1
Q
2
W
3
E
4
Q
5
Q
6
R
7
Q
8
W
9
Q
10
W
11
R
12
W
13
W
14
E
15
E
16
R

Guide to Countering 大发明家 as 虚空之眼

Tips for Playing as 虚空之眼 against 大发明家

- 要非常谨慎地挑选终极技能的使用时机。大部分英雄的技能都可以打断这个技能。

- 侧身发射等离子裂变,并让它在最大距离处分裂,就能让这个技能命中初始施法距离之外的敌人,这也是一个值得去掌握的技巧。

- 在对线时,使用虚空裂隙来击杀小兵,同时在敌方英雄身上叠加有机体解构效果。然后你可以接其它技能。

Advice to Win Against 大发明家

- 要当心黑默丁格的终极技能,因为他能用终极技能来化解当前他所遇到的大部分麻烦。一旦他交出终极技能,就可以准备击杀他了!

- 黑默丁格召唤炮塔后,尽快伙同你的队友摧毁炮塔。炮塔聚集在一起后会变得很强力。

虚空之眼 vs 大发明家 Counter Stats

虚空之眼 Image
winRate
49.2 %
VS
winRate
50.8 %
大发明家 Image
5.7
< kills >
4.7
6
< deaths >
6.4
8.6
< assists >
6.9
1.27
< killingSprees >
1.04
94
< cs >
138
0.1
< dragons >
0.18
0.45
< inhibitors >
0.5
465
< physicalDamage >
745
18,248
< magicDamage >
23,562
5,701
< trueDamage >
686
24,416
< damageDealt >
24,994
18,888
< damageTaken >
21,461
10,661
< goldEarned >
11,145
1.65
< towers >
2.02
0.02
< barons >
0.07
2,066
< heal >
2,304
13,001
< xp >
14,181
42
< visionScore >
29
19
< wardsPlaced >
13
233
< ccTime >
271

How to Counter 大发明家 with 虚空之眼 in LoL

The stat comparisons shown on this page underscore some valuable 虚空之眼 against 大发明家 counter statistics that can help us grasp the differences between the two. For instance, 虚空之眼’s KDA ratio ([kills + assists] / deaths) of NaN is greater than 大发明家’s KDA ratio of NaN, showing that 虚空之眼 may be more central to his team's team fighting capability than 大发明家..

虚空之眼 normally has a similar longest killing spree as his counter does. Commonly, he takes a similar amount of damage to 大发明家. This commonly reflects different amounts of tankyness; however, it can also show that the one champ has less mobility and thus is not able to flee from additional harm when poked or engaged.

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伤害数据

虚空之眼
大发明家
物理伤害
魔法伤害
真实伤害

championDifferences.playStyle.title

虚空之眼
大发明家

championDifferences.whoIsBetter

Both League of Legends champs are great champions. Both champs have their strengths, weaknesses, and counters. In the game's current meta, 虚空之眼 usually fairs equally well when trying to fight 大发明家, with a 49.2% win rate. As a result, 虚空之眼 makes an ok counter to 大发明家.

While 虚空之眼 does have a lower winrate compared to 大发明家, when facing one another, 虚空之眼 also has a greater level of difficulty that makes him a more complex champion to develop with. You should be careful when picking 虚空之眼 into 大发明家as his relative depth means that you may not be able to reach his full potential without a lot of practice beforehand.

Furthermore, 虚空之眼 has some amount of utility and CC, a similar amount to 大发明家. This makes her just as valuable during team fights, especially when trying to counter champions with a lot of burst damage.

While there is not a single best champion overall in League of Legends, in 虚空之眼 vs 大发明家 matchups, 大发明家 is the better champ with a similar win rate, similar champion depth, and a similar amount of utility to help out your teammates during teamfights.

虚空之眼 is a somewhat poor counter to 大发明家. Focus your gameplay on maximizing your gold and cs and taking out objectives. If you do that, you should be able to stand on your own as 虚空之眼 against 大发明家.

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If you would like to learn all of the intricacies of 虚空之眼 to counter 大发明家 during both the early game and mid / late game phases of League of Legends, you should continue reading to learn a few extra lessons on this matchup. If you pay attention to the build and stats shown above, you should grow your win rate significantly and be that much closer to League of Legends pro players.

虚空之眼 typically picks up a similar amount of CS compared to 大发明家. Champs who on average don't earn much CS often don't need much CS to be valuable teammates, such as sup champs. They are able to scale properly off of their abilities and first items alone. Yet, champs with a lot of CS, such as hyper-carries, often need several high cost items to be effective. In either situation, try to do better than the values reported here to do well.

The top items to prioritize in your 虚空之眼 versus 大发明家 build include 残疫, 扎兹沙克的溃口, and 卢登的伙伴. When 虚空之眼 combined at least these three items in his build, he did much better countering 大发明家 than with most other common builds. In fact, 虚空之眼 had an average win rate of 49.2% when playing against 大发明家 with this build.

To have the greatest probability of crushing 大发明家 as 虚空之眼, 虚空之眼 players should use the 奥术彗星, 法力流系带, 超然, 焦灼, 饼干配送, and 星界洞悉 runes from the 巫术 and 启迪 rune sets. Out of all the rune combinations players picked for 虚空之眼 vs 大发明家 face-offs, this combination of runes yielded the best win rate. In fact, these runes averaged a 49.2% winrate overall.

By default, tips, statistics, and builds on how to beat 大发明家 as 虚空之眼 are displayed for all ranked divisions. If you want to narrow the stats and builds to a particular skill level, you may use the selection menu located earlier on the page.