荆棘之兴 with 大发明家
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第一项
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Core 荆棘之兴 Items
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Summoner Spells
技能顺序
符文
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- 种子可以为你的队伍提供视野，请好好利用。
- 在你的技能施放之后，再往你的技能路径上播下种子，可以确保你的种子能够百分百变成植物。
- 婕拉是一个出色的伏击手——寻找时机，然后在草丛里布下陷阱，再诱引敌人进来。
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- 对于黑默丁格的生存而言，【E电子风暴手雷】的成功命中是非常重要的。减速和晕眩效果都能让敌人乖乖呆在远处被你痛揍，但它也是对付敌方奇袭的第一道防线。
- 炮塔的布局是战斗中一个决定性因素。对于大多数敌人，扎堆放置炮塔来攻击敌人是最佳方法，但如果敌人有很多群伤技能，那么你的防御塔可能很快就会被摧毁。此外，将炮塔放置在草丛中，可以进行有利于己方的突袭。
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The 荆棘之兴 大发明家 synergy stats shown here demonstrate the areas of her gameplay that do better (or worse) when paired with 大发明家, compared to her overall stats. Significant differences are areas of focus that highlight how her gameplay changes when paired with this other champion.
Overall, 荆棘之兴 sees a large worsening in her KDA (ratio of kills and assists to deaths) when paired with 大发明家. His KDA decreased from NaN to NaN. This worsening shows that 大发明家 helps 荆棘之兴 perform poorer in ranked LoL matches. Yet, the small difference demonstrates that this performance change is not very impactful.
When 荆棘之兴 tries to synergize with 大发明家, she gets a little drop in her full damage dealt. This difference could demonstrate that 大发明家 does not help protection for her to dish out more damage or that his presence also helps extend the round's duration. Similarly, when 荆棘之兴 is played together with 大发明家 on the same team, he usually scores many fewer killing sprees than when she plays alone. This is contrasting evidence that she is worse when playing synergisticly with 大发明家.
Additionally, when 荆棘之兴 plays with 大发明家 on the same team, she usually takes a little more damage than when she fights alone. Getting dealt more damage may mean that 大发明家 does a poor job of protecting 荆棘之兴 during team fights.
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伤害数据
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There is no perfect champion pairing for 荆棘之兴 that will always be her top synergy. Yet, 大发明家 is a very typical ally for 荆棘之兴. By locking into the same side as 荆棘之兴, he drops their win rate by -0.3% to 52.3%. This proves that there is a weak bond between 荆棘之兴 and 大发明家 that allows them to perform worse together than without each other.
大发明家 has a greater difficulty than 荆棘之兴. That means you should be careful when finding 大发明家 allies to go into battle on the same side as, as they will require a greater level of skill to be able to work well with you.
When playing together, 荆棘之兴 players should expect to observe an overall large increase in your team’s ability to deal magical damage. When paired, these champs can deal quite a lot of AP type damage.
Although, by pairing 荆棘之兴 and 大发明家 together, you may not be giving your other teammates much anti-tank damage dealing potential. We recommend you pick other champs on your team that nullifies this relative disparity in their potential.
Regardless of the skill of your 大发明家 teammate, you need to focus on maximizing your income, staying alive by avoiding foolish fights, and taking down objectives. If you heed this simple advice, you should do well, regardless.
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To truly master 荆棘之兴 in order to work well with 大发明家 during both the early game and mid / late game phases of League rounds, you should keep reading to learn some more tips and tricks for this champion pairing. If you pay attention to the build and tips displayed above, you should increase your win rate significantly.
The best items to get in your 荆棘之兴 and 大发明家 synergy build include 中娅沙漏, 扎兹沙克的溃口, and 兰德里的折磨. When 荆棘之兴 bought at least these three finished items in her build, she performed much better when fighting alongside 大发明家 than with most other commonly used item sets. In fact, 荆棘之兴 boasted an average win rate of 52.3% when playing alongside 大发明家 with this build.
To have the highest likelihood of vanquishing your oponents, 荆棘之兴 players should equip the 奥术彗星, 法力流系带, 超然, 焦灼, 无情猎手, and 血之滋味 runes from the 巫术 and 主宰 rune sets. Of all the rune builds players used for this team composition, this blending of runes resulted in the highest win rate. Moreover, these runes provided a 52.3% winrate overall.
If you would like to see 荆棘之兴 with 大发明家 cooperations tips and builds for a a specific division rank, feel free to select one from the selection menu above. If viewing for the first time, the statistics and strategies shown are computed using all rounds finished with both champs.